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27y^2-6y-8=0
a = 27; b = -6; c = -8;
Δ = b2-4ac
Δ = -62-4·27·(-8)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-30}{2*27}=\frac{-24}{54} =-4/9 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+30}{2*27}=\frac{36}{54} =2/3 $
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